![[asy] draw((0,0)--(3,0)); draw((0,0)--(0,2)); draw((0,2)--(3,2)); draw((3,2)--(3,0)); dot((0,0)); dot((0,2)); dot((3,0)); dot((3,2)); draw((2,0)--(2,2)); draw((0,1)--(2,1)); label("C",(0,0),S); label("D",(3,0),S); label("B",(3,2),N); label("A",(0,2),N); [/asy]](https://latex.artofproblemsolving.com/e/6/b/e6bc996438912f0186845a049211eb31adce2d9b.png)
We know that the shortest sides (so half of AC) is 5 feet. That means that the length of AC is 5 ⋅ 2 = 10 feet.
Because AC is 10 feet, the longer side of one rectangle is 10 feet. That makes the area of a smaller rectangle 5 ⋅ 10 = 50 feet².
There are 3 of those smaller rectangles, so the total area is 50 ⋅ 3 = 150 feet², making the answer E.
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